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  1. import java.util.Scanner;
  2.  
  3. public class Main {
  4.     public static int maxSubarraySum(int[] b) {
  5.         int n = b.length - 1; // Adjust for 1-based indexing
  6.         if (n == 0) return 0;
  7.  
  8.         int T = 0; // Initialize T to 0, which will store the maximum sum subarray
  9.         int prv = 0; // Initialize prv to 0, which will store the current maximum sum subarray ending at b[i]
  10.  
  11.         for (int i = 1; i <= n; ++i) {
  12.             int current = Math.max(prv + b[i], b[i]);
  13.             current = Math.max(current, 0);
  14.             prv = current;
  15.             T = Math.max(T, current);
  16.         }
  17.  
  18.         return T;
  19.     }
  20.  
  21.     public static void main(String[] args) {
  22.         Scanner scanner = new Scanner(System.in);
  23.  
  24.         int n = scanner.nextInt();
  25.         int[] b = new int[n + 1]; // Adjust for 1-based indexing
  26.         for (int i = 1; i <= n; ++i) {
  27.             b[i] = scanner.nextInt();
  28.         }
  29.  
  30.         int result = maxSubarraySum(b);
  31.         System.out.println("Maximum subarray sum is " + result);
  32.     }
  33. }
  34.  
Success #stdin #stdout 0.21s 56904KB
comments (?)
stdin
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1
5
stdout
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Maximum subarray sum is 5
https://ideone.com/9aNLaq
language:
Java (HotSpot 12)
created:
2 days ago
visibility:
public

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