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  1. // Minimum Time (Binary Search on Answer)
  2. #include <bits/stdc++.h>
  3. using namespace std;
  4.  
  5. bool canMake(vector<int>& t, int k, long long time) {
  6.     long long total = 0;
  7.     for(int x : t) total += time / x;
  8.     return total >= k;
  9. }
  10.  
  11. int main() {
  12.     int n = 3, k = 7;
  13.     vector<int> t = {2,3,5};
  14.  
  15.     long long l = 1, r = 1e18, ans = 0;
  16.  
  17.     while(l <= r) {
  18.         long long mid = (l + r) / 2;
  19.         if(canMake(t, k, mid)) {
  20.             ans = mid;
  21.             r = mid - 1;
  22.         } else l = mid + 1;
  23.     }
  24.  
  25.     cout << ans;
  26. }
Success #stdin #stdout 0.01s 5288KB
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https://ideone.com/BaRlZ0
language:
C++ (gcc 8.3)
created:
18 hours ago
visibility:
public

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