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  1. #0JrQsNGB0YzRj9C90LXQvdC60L4=
  2. a=1
  3. b=4
  4. c=3
  5.  
  6. D = b**2-4*a*c
  7. if(a==0):
  8.     print("ERROR: a=0, equation is linear")
  9. else:
  10.     if D>0:
  11.         sqrt1 = (-b-D**0.5)/(a*2)
  12.         sqrt2 = (-b+D**0.5)/(a*2)
  13.         print(f"{a}x^2+{b}x+{c}=0")
  14.         print(f"x1 = {sqrt1}")
  15.         print(f"x2 = {sqrt2}")
  16.         print("------------------")
  17.         print(f"{a}x^2+{b}x+c>0")
  18.  
  19.         if(a>0):
  20.             print(f"x є (-∞;{sqrt1})U({sqrt2};+∞)")
  21.         else:
  22.             print(f"x є ({sqrt1};{sqrt2})")
  23.     elif D==0:
  24.         sqrt1 = -b/(2*a)
  25.         print(f"{a}x^2+{b}x+{c}=0")
  26.         print(f"x = {sqrt1}")
  27.         print("------------------")
  28.         print(f"{a}x^2+{b}x+c>0")
  29.         if(a>0):
  30.             print(f"x ≠ {sqrt1}")
  31.         else:
  32.             print("x є Ø")
  33.     else:
  34.         print(f"{a}x^2+{b}x+{c}=0")
  35.         print("x є Ø")
  36.         print("------------------")
  37.         print(f"{a}x^2+{b}x+{c}>0")
  38.         if a>0:
  39.             print("x є R")
  40.         else:
  41.             print("x є Ø")
  42.  
Success #stdin #stdout 0.11s 14080KB
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1x^2+4x+3=0
x1 = -3.0
x2 = -1.0
------------------
1x^2+4x+c>0
x є (-∞;-3.0)U(-1.0;+∞)
https://ideone.com/LWHrAP
language:
Python 3 (python  3.12)
created:
6 days ago
visibility:
public

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