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  1. int main(){
  2. 	long long a,b,c,i;
  3. 	long long d=2, e=2;
  4. 	scanf("%llu %llu %llu",&a,&b,&c);
  5. 	for (i=1;i<=63;i++){
  6. 		d=2*i*d;
  7. 		printf("%llu\n", d);
  8. 	}
  9. 	for (i=1;i<=63;i++){
  10. 		e=2*e;
  11. 	}
  12. 	printf("%llu \n%llu", d-1, e-1);
  13. 	return 0;
  14. }
Success #stdin #stdout 0.01s 5212KB
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18446744073709551615 
18446744073709551615
https://ideone.com/Nd6d5k
language:
C (gcc 8.3)
created:
14 days ago
visibility:
public

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