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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int n, i=1, p=0,q=1;
  5.  
  6. 	scanf("%d",&n);
  7.  
  8. 	while(i<=n){
  9. 		p =p+2*q;
  10. 		i = i + 1;
  11. 		q=q*3;
  12. 		}
  13. 	printf("和: %d",p);
  14.  
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0.01s 5320KB
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4
stdout
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和: 80
https://ideone.com/Q05bYG
等差数列の和（初項２、公差３）
language:
C (gcc 8.3)
created:
10 days ago
visibility:
public

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