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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a=3, n=0;
  5. 	while(a<10000)
  6. 	{
  7. 	a = 2*a - 1;
  8. 	n += 1;
  9. 	}
  10. 	printf("数列が10000を超えるとき、a_(%d)=%dである",n,a);
  11.  
  12. 	return 0;
  13. }
  14.  
Success #stdin #stdout 0s 5304KB
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数列が10000を超えるとき、a_(13)=16385である
https://ideone.com/UnJ49S
language:
C (gcc 8.3)
created:
10 days ago
visibility:
public

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