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  1. #include <stdio.h>
  2.  
  3. int main() {
  4.     int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  5.     int n = 10;
  6.     int k = 3;
  7.     int prefix[n];
  8.     prefix[0] = arr[0];
  9.     for (int i = 1; i < n; i++) {
  10.         prefix[i] = prefix[i - 1] + arr[i];
  11.     }
  12.     int total = 0;
  13.     for (int i = 0; i <= n - k; i++) {
  14.         int sum;
  15.         if (i == 0)
  16.             sum = prefix[k - 1];                   
  17.         else
  18.             sum = prefix[i + k - 1] - prefix[i - 1];  
  19.  
  20.         total += sum;
  21.     }
  22.  
  23.     printf("Sum of all subarray sums: %d\n", total);
  24.     return 0;
  25. }
Success #stdin #stdout 0s 5316KB
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stdin
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Standard input is empty
stdout
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Sum of all subarray sums: 132
https://ideone.com/VCjxEI
language:
C (gcc 8.3)
created:
19 hours ago
visibility:
public

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