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  1. int hex(int n){
  2.     int H[850], i;
  3.     H[1] = 1;
  4.     for(i = 2;i<=n; i++){
  5.         H[i]=H[i-1]+6*i-6;
  6.     }
  7.     return H[n];
  8. }
  9. int main(){
  10. 	printf("%d",hex(3));
  11. }
Success #stdin #stdout 0s 5320KB
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19
https://ideone.com/bBBuSX
language:
C (gcc 8.3)
created:
10 days ago
visibility:
public

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