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  1. #include <stdio.h>
  2. int main(void)
  3. {
  4.     int data1, data2;
  5.     char op;
  6.     printf("Please enter an expression:");
  7.     scanf("%d%c%d", &data1, &op, &data2); // 输入运算表达式
  8.     switch (op)                          // 根据输入的运算符确定执行的运算
  9.     {
  10.     case '+':                            // 加法运算
  11.         printf("%d+%d = %d\n", data1, data2, data1 + data2);
  12.         break;
  13.     case '-':                            // 减法运算
  14.         printf("%d-%d = %d\n", data1, data2, data1-data2);
  15.         break;
  16.     case '*':                            // 乘法运算
  17.         printf("%d * %d = %d\n", data1, data2, data1 * data2);
  18.         break;
  19.     case '/':                            // 除法运算
  20.         if (data2 == 0)                  // 为避免除0错误,检验除数是否为0
  21.             printf("Division by zero!\n");
  22.         else
  23.             printf("%d/%d = %d\n", data1, data2, data1 / data2);
  24.         break;
  25.     default:                             // 处理非法运算符
  26.         printf("Invalid operator! \n");
  27.     }
  28.     return 0;
  29. }
Success #stdin #stdout 0s 5316KB
comments (?)
stdin
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556+332
stdout
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Please enter an expression:556+332 = 888
https://ideone.com/uDEN6c
language:
C (gcc 8.3)
created:
12 hours ago
visibility:
public

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