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  1. #include <stdio.h>
  2.  
  3. int n, a[105][105], X[105],cot[105], cheo1[105], cheo2[105];
  4.  
  5. void Try(int i){
  6.     for(int j = 1; j<= n; j++){
  7.         if(cot[j] == 0 && cheo1[i-j+n] == 0 && cheo2[i+j-1] == 0){
  8.             X[i] = j;
  9.             cot[j] = 1, cheo1[i-j+n] = 1, cheo2[i+j-1] =1;
  10.             if(i == n){
  11.                 for(int i = 1; i<=n; i++){
  12.                     for(int j = 1; j<= n; j++){
  13.                         if(X[i] == j){
  14.                             printf("Q");
  15.                         }
  16.                         else{
  17.                             printf(".");
  18.                         }
  19.                     }
  20.                     printf("\n");
  21.                 }
  22.                 printf("\n");
  23.             }
  24.             else{
  25.                 Try(i+1);
  26.             }
  27.             cot[j] = 0, cheo1[i-j+n] = 0, cheo2[i+j-1] = 0;
  28.         }
  29.     }
  30. }
  31. int main(){
  32.     scanf("%d",  &n);
  33.  
  34.     Try(1);
  35. }
  36.  
Success #stdin #stdout 0s 5296KB
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https://ideone.com/wLQkTU
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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