import sys
def main():
# n = int(input())
# r1, c1 = map(int, input().split())
# r2, c2 = map(int, input().split())
input_lines = iter(sys.stdin)
n = int(next(input_lines))
r1, c1 = map(int, next(input_lines).split())
r2, c2 = map(int, next(input_lines).split())
# Ensure Blue is on the left side.
if c1 > c2:
c1 = n - c1 + 1
c2 = n - c2 + 1
s = c1 + c2
if r1 == r2:
columns_taken1 = s >> 1
blue_win = columns_taken1 > (n >> 1)
else:
# Let's assume Blue is in the top row.
# They go towards each other.
# The question is what to do near the meet point?
diff = c2 - c1
if diff == 0:
blue_win = False
elif diff == 1:
cells_taken1 = max(
diff + 1 + ((n - c2) << 1), # moving right
s - 1 # moving down
)
blue_win = cells_taken1 > n
elif diff & 1:
# Let's calculate how many cells Blue can take if Red moves
# to the left near the meet point:
cells_taken1 = max(
diff + 1 + ((n - c2) << 1), # moving right
s - 1 # moving down
)
# Now let's calculate how many cells Red would take:
cells_taken2 = max(
(n - (s >> 1) - 1) << 1, # moving up
(n << 1) - cells_taken1 # moving left
)
blue_win = cells_taken2 < n
else:
# Let's calculate how many cells Red can take if Blue moves
# to the right near the meet point:
cells_taken2 = max(
((c1 - 1) << 1) + (diff | 1), # moving left
(n << 1) - s # moving up
)
# Now let's calculate how many cells Blue would take:
cells_taken1 = max(
s - 2, # moving down
(n << 1) - cells_taken2 # moving right
)
blue_win = cells_taken1 > n
if blue_win:
print("Blue")
else:
print("Red")
if __name__ == "__main__":
main()
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